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2m^2-6m=92m
We move all terms to the left:
2m^2-6m-(92m)=0
We add all the numbers together, and all the variables
2m^2-98m=0
a = 2; b = -98; c = 0;
Δ = b2-4ac
Δ = -982-4·2·0
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9604}=98$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-98}{2*2}=\frac{0}{4} =0 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+98}{2*2}=\frac{196}{4} =49 $
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